InfoPath Dev

Oops sorry.  I've opened the data source (control) and screen shot that.  Is this what you're looking for?

I was super hopeful that would work, but alas when I preview and choose BREC the section is still not showing up.  Any other thoughts?   **Update... it DOES work if I'm using a repeating section with dropdowns, but I'd like to be able to use the multi-selction field rather than dropdowns.  That's when it doesn't ...

It seems you have attached a screenshot of the form's layout, but not its data source.  I need to see what the data source looks like in order to help you.

Stuck in the middle of designing a form so KINDA URGENT PLEASE 1. I need to add some dummy fields to a form but I dont want those fields to be added to the SP List. 2. According to this guy http://www.bizsupportonline.net/blog/2008/11/how-to-create-a-hidden-field-in-infopath/ (Bullet # 1). It's done at time time of Infopath ...

Have attached a screen shot.  In the drop down, have options of selecting 'pass' 'finding' or 'discrepancy'.  Thanks.

That would depend on how your data source is structured.  Could you attach a screenshot of enough to give us an idea of how you've organized it?

I like easier ways...  I have a checklist asking a question with a drop down control with answers (these are the ones I want to count) and then a comment text box.  I've used the count method you mention above, however, it limited me on the number of fields I could count to something like 40 (ish).  I have 182 questions.  ...

I think you have it almost right here: Hide when Organization does not equal BREC In the left dropdown box, pick Select field or group, select Organization and then from the dropdown at the bottom of that selection dialog, pick All instances of so you wind up with: Hide when All instances of Organization are not equal to BREC I believe that ...

If you go to edit a view in your list, you'll see the ID. All list and library items in SharePoint have an ID - it is an auto-incrementing identity column and unique per list / library (i.e., in a given list, there will only be one item "1" and the id will never be re-used if the item is deleted). Your item B above sounds not quite ...

Depending on your data source is organized, there may be a simpler way, but generally for disparate fields, the way to count how many have a certain value is:count((firstField | secondField | ... | lastField)[. = 'pass'])