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Can you attach your template again?
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I noticed that after I posted. I do not have any custom code in the template but have seen this happen before.(you helped me previously and the issue was with the custom code even though I had not added any)
I removed the code and re-injected the form. Still have the same problem.
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I've created an InfoPath 2010 form and one of my fields is set as a PERSON/GROUP PICKER. RIGHT-CLICK on the PEOPLE PICKER box and select PROPERTIES. Then on the GENERAL tab, check the box next to ALLOW MULTIPLE SELECTIONS. Click OK and publish form to site. Then when I go to the SP site and try to add a new item to my list, I try ...
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Looks like custom code was accidentally added to the form. Go to Form Options / Programming and click the remove code button and save, then re-inject, unless your custom code is intentional? If so, let me know and I'll get you a link to a doc on how to do that.
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You just need this part:
../my:RevTable/my:RevGroup[last()]/my:QPRev
The last() function goes on the repeating group.
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I have a form that I have been using for quite some time. I had to update my qrulesfrom 4.2 to 4.3 due to a MS ticket I had opened, and now my Qrules commands are not working. This form has the submit to sharepoint command, DateDiff and others. The DateDiff command that is on the EventEndDate field does not return a Result ...
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Well - you are using an absolute XPath which will get the first one, sure. Is the ID for the hyperlink a field inside the group? Use a relative XPath to get what you need - ../ will take you from the ID to the group (if it is a first level child inside the group - sorry, I've got no idea what your data structure looks like) - so you ...
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../my:RevTable/my:RevGroup[last()]../my:RevTable/my:RevGroup/my:QPRev
If you want to e-mail me, can send you the form itself. I am at judy.havlik@plitek.com
I can't tell you how much I appreciate the time you're taking.
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Ok so that would work but the node that I need isn't actually the same one that gets clicked. It is in the same group but it is the ID of the hyperlink. Is there a way to get that name without doing SelectSingleNode because that just gets the first instance.
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Can you paste in exactly what you have in the formula editor? Check the Edit XPath box first... :)