InfoPath Dev

I am trying to use the "Look up values in the form's data source" feature of a Drop-Down List, but I always get the following error:

InfoPath cannot create a new, blank form.
The form template is not valid.

InfoPath cannot open the following view: View 1
The following view file is not valid: view1.xsl
The .xsl file is not valid XSL.
Expected token ')' found '['.

not(../..-->[<--@my:UniqueID=$val] or $val='')

The referenced XSL is:
<xsl:variable name="val" select="."/>
<xsl:if test="not(../..[@my:UniqueID=$val] or $val='')">

Can you give us the xml file that is being used in the solution and which field you are trying to bind to the dropdown?

Shanthi
InfoPathDev India

I believe that you cannot have a filter ([]) directly after a self (.) or parent (..) reference.

You might try updating the XPath to something like the following:

<xsl:if test="not(../..node()[@my:UniqueID=$val] or $val='')">


Greg Collins [InfoPath MVP]
InfoPathDev

As far as I can tell, the problem is that I am using a data element as the source for a combo box which is bound to an element which is _contained_in_ the hierarchy of the source element.

e.g.:
schema:
<items>
<item>
<name/>
<item-id/>
<references>
<reference-id/>
<reference-id/>
</references>
</item>
</items>

combobox bound to <reference-id>
combobox data source specified as <item>
using display: <name>
using value: <item-id>
xpath for selectable <item>s should be: "/items/item"
actual xpath determined by InfoPath: "../../item"

Hello timcoffman,
I tried creating the same schema that you mentioned above and set the dropdown as you mentioned. The solution worked for me in preview. I had a repeating table for Items block and as i inserted new items, these new values were seen in the dropdown control.

Is there anything that I'm missing? The xpath for the selectable item is "/my:myFields/my:items/my:item" in the solution that I just created

Shanthi
InfoPathDev India