InfoPath Dev

Hi everyone,

Is it possible to use code to run through all elements in the DataSource and display the output of each field. (ie: via a while loop)

Also, is this possible to do this for a given folder within the DataSource?

Hi,
Try this XPath you should be able to get all the child nodes with it.
node.selectNodes("descendant::*");
then loop through these nodes and output those values where ever you want.

Agni
INFOPATHdev India

Hi Agni,

Thanks for your reply, but I am confused with your example code.

I'll try to clarify my question:
Pretend I have 5 field(elements), under the myFields group. I want to run some code which will find all fields under the myFields group and then display the fields value one at a time.

From your code, I'm not sure what node is. I would assume that node is a variable, that is the group that I want to start the search from. However, I am not sure how to create such a variable.
I would guess:
var node = XDocument.DOM.selectSingleNode("/my:myFields");
but that doesn't feel right.

I am also confused when you said loop through the nodes, as I am confused how to do this as well.

Any help would be greatly appreciated.

Thanks

- Reg.

Hello,
When you do a selectNodes you will get all of the nodes as a nodelist. Then you can have a for each loop that will walk through all of these nodes and get the information that you need.

Hi Shanthi,

Thanks for your reply.

I tried the selectNodes idea that was given before by Agni, but as noted I couldn't get it to work.

When I tried again, I noticed the length of the nodelist is always 1.
I however noticed that it shows the number of a repeating section, but this is not what I wanted.

After searching the internet, I found an example of how you can get the childNodes of a given element (I can't remember which site it was from now, but believe it was another InfoPath Dev Site). I then added to the code to make it work for me and managed to get all the descendants by running through the nodes in a recursive manner.
(I've attached some code at the bottom of this comment)

If I am wrong about the selectNodes not being able to select all Nodes in a dataSource, could you please verify that.

Thanks again for your input.

Regards,

- Reg.


Code example:
-----------------------

function CTRL2_5::OnClick(eventObj)
{
var theNode = XDocument.DOM.selectSingleNode("/my:myFields");
getDescendants( theNode );
}

function getDescendants( Node )
{
var nodeList = Node.childNodes;
var item;

for (var i = 0; i < nodeList.length; i++)
{
item = nodeList.item(i);

// if the item is an element in the dataSource,
// and not the elements "text".
if ( item.nodeType == 1 )
{
// Outputs the item's value
XDocument.UI.Alert( item.text )

// find the descendants of the current node
getDescendants( item );
}
}
}

Hi rjohnson,

I think you're wasting your time with this getDescendents() function! It's already implemented as an XPath axis. Check out this tutorial:

http://www.w3schools.com/xpath/xpath_axes.asp

Also, run this code snippet to get a feel of what's going on:

	var nl = XDocument.DOM.selectNodes( "/my:myFields/descendant::*" );
	var str = "";
	
	while( (node = nl.nextNode()) != null )
	{		
		//str += node.xml;	
		//str += node.text;	
		str += node.nodeName;	
		str += "\n------------\n";
	}
		
	//XDocument.DOM.selectSingleNode( "//my:field7" ).text = str;
	XDocument.UI.Alert( str );

Hi Matt,

Thanks for your solution,

I didn't know how to use selectNodes to get all the descendants, but I now do, thanks to your example.

Cheers,

- Reg.