InfoPath Dev

I know there is a rule to do this, but I need to do it via code. I got a navigator to the datasource and was expecting to see XML with atributes like URL etc. but see nothing.

Is this at all possible & how?

Thanks

 I think you instead need to look at the data connection and change the URL there: http://msdn.microsoft.com/EN-US/library/microsoft.office.infopath.webserviceconnection.aspx might help.

 Hilary is absolutely right about interacting with the data connection object, but REST connections inherit from the FileQueryConnection class:

FileQueryConnection conn = (FileQueryConnection)DataConnections["REST Web Service"];
conn.FileLocation = "http://server/someservice.svc?param1=a&param2=b";
conn.Execute();

These 3 lines of code is exactly what I wanted. I'm still a bit confused about the difference between a DataSource and a DataConnection though. Will need to read the docs.

Thanks both.

Thanks, Jimmy - I hadn't realized that!

Graeme:

I'm still a bit confused about the difference between a DataSource and a DataConnection though.

They are essentially one and the same, but as far as the code goes, you use a DataSource object to access a data source's XML data, and use a DataConnection object to access its properties and/or execute it.

Hello, I am trying to get the current form in order to print it, also the print function is controled by a button on the form. There could be as many as 8 forms open at once for the user, so I need to find the correct one in order to print it.