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  • Re: Conditional counting

    I think I&#39;m a bit confused over what you mean. Is there a way to use a conditional statement in square brackets such that the entry on a node can be changed individually rather than the whole lot? Everything I try seems to add numbers to every HQuantity at once, but I only want to add&nbsp;a count of users for a given order&nbsp;to the ...
    Posted to General (Forum) by ben.oates on 11-14-2007
  • Re: Conditional counting

    Almost. I want to know how many users want the hardware/software rather than how many overall orders there are for them. I have a list of hardware, software and users uniquely identified. The user then compiles orders where a piece of hardware may be chosen. I want the quantity for that piece of hardware to reflect a sum of the&nbsp;user ...
    Posted to General (Forum) by ben.oates on 11-12-2007
  • Re: Faxing - the holy grail.

    I haven&#39;t looked into direct faxing from&nbsp;Infopath but I do have an idea for a possible workaround. My friends use an online automated faxing company where they e-mail the content to a server which then faxes it to the phone number in the subject field. This should be relatively easy for you to set up as a submit action.
    Posted to General (Forum) by ben.oates on 11-10-2007
  • Conditional counting

    Hi all, I&#39;m probably overcomplicating this but I am trying to create a form where I can add hardware, software and users and then set configurations in orders. What I want to do is count the number of users in each order for each piece of software and hardware if it is selected in that order. Each hardware/software entry exists in a ...
    Posted to General (Forum) by ben.oates on 11-10-2007
  • Re: Create Unique ID w/o a lot of programming

    Are you trying to create a unique ID for the form or within a repeating node? Sharepoint assigned a unique ID to every form that has been submitted and you can make that visible in a view. If you are trying to uniquely number nodes you can count the preceeding siblings in a function like this: count(../preceding-sibling::my:elementName) + ...
    Posted to Newbie Questions (Forum) by ben.oates on 11-10-2007
Page 6 of 6 (55 items) « First ... < Previous 2 3 4 5 6
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