InfoPath Dev

But, if you go to Tools \ Data Connections \ Add \ Receive Data \ XML (let's say Form1.xml) When you extract your files, your should see your Form1.xsd (which is already embedded in the form). You should be able to look at the schema through the data source drop-down. Am I missing something here? Regards, Franck Dauché InfoPathDev

Hi Abhishek, Check this:http://www.infopathdev.com/forums/topic.asp?TOPIC_ID=431 Regards, Franck Dauché InfoPathDev

oops....Jason, I have to take the blame for this...sorry, I meant vt. Franck

Hi Kelly, You open a new VB.Net project, you add a reference to System.Data. You drop 1 button and the form and write the code that you posted, with the connection string on 1 single line. You run and it works. If you did that and are still experiencing issues, the only difference between your code and mine would be the database (an Access 2003 ...

nope, I don't think backslashes are required....I actually tested the code myself on a VB-based project, and it works fine. That's why I think that Kelly may have an issue with the db itself. Franck

Hi Adam, you could try 2 things: 1. Work with your attributes as if they were nodes, not attributes (if you built your schema using InfoPath). 2. Keep you code but create your schema with XMLSpy. Tell me if it helps. Regards, Franck Dauché InfoPathDev

- You can open your mdb manually, right? It is not corrupted? - You have your reference to System.Data? Regards, Franck Dauché InfoPathDev

Hi, You have secondary data sources for your lists then, right? You can loop through your secondary DOM by code (do a search on this forum for code sample), and just assign the value you need to the node in your main DOM (thisXDocument.DOM.selectSingleNode(''YourXPath'')). Regards, Franck Dauché InfoPathDev

Hi Vasudha, Yes, just pre-populate your node linked to your DDL with the initial value you wish to have. Regards, Franck Dauché InfoPathDev

Hi Richard, Earlier, you mentioned VBScript or VB.Net, the line I gave you is VB.Net. You posted JScript. In that case, the event is ''eventObj'', not ''e''. Regards, Franck Dauché InfoPathDev