InfoPath Dev

I have an IP 2003 form with C# code. I would like to add a button that will open up a new form in a different view. I am using the following code: XDocument NewForm = thisApplication.XDocuments.NewFromSolution(@"C:\Users\Lawson\Desktop\Switch View.xsn"); thisXDocument.View.SwitchView("View 2"); This code opens a new form, ...

Can you try running this in IP 03 compatable mode to see if it will work with InfoPath 2003?  Thanks for your help, -Lawson

I have an IP 2003 form with C# code. I would like to add a button that will open up a new form in a different view. I am using the following code: XDocument NewForm = thisApplication.XDocuments.NewFromSolution(@"C:\Users\Lawson\Desktop\Switch View.xsn"); thisXDocument.View.SwitchView("View 2"); This code opens a new form, ...

I have an IP 2003 form with C# code. The form has many attachment fields. I need to get the names of attachments and the document type from the attachment and place it in an output. Does anybody know how to get the file name and document type from an attachment in an InfoPath 2003 form? Example: document.doc  Thanks, -Lawson

I tried this, but I got over a dozen errors...

Will the local variable "filename" give me the output I need?

I have an IP 2003 form with C# code. The form has many attachment fields. I need to get the names of attachments and the document type from the attachment and place it in an output.   Does anybody know how to get the file name and document type from an attachment? Example: document.doc Thanks, -Lawson  

I have an IP 2003 form with C# code. I would like to add a button that will open up a new form in a different view. I am using the following code: XDocument NewForm = thisApplication.XDocuments.NewFromSolution(@"C:\Users\Lawson\Desktop\Switch View.xsn"); thisXDocument.View.SwitchView("View 2"); This code opens a new form, ...

 I get an error message.  NewForm method does not exist.

I am using the following code: XDocument NewForm = thisApplication.XDocuments.NewFromSolution(@"C:\Users\Lawson\Desktop\Switch View.xsn"); thisXDocument.View.SwitchView("View 2");   This code opens a new form, but it doesn't change the view in the new form. Does anybody have any suggestions?