InfoPath Dev

Is it possible to calculate Sums Square on a repeating table in InfoPath 2010. If so, how does one go about doing the calculation? Thanks.

Hi There,I have the following problem, and feel like I have exhausted google as a resource for information. I have an InfoPath 2007 form, which users fill in to create orders that contains a repeating table for multiple items to be ordered at one supplier. The form also creates a continuous purchase order number, which serves as a unique ...

Hi, Firstly I find this forum very informative with a lot of timely suggested solutions. Am stuck with a strange situation and any help would be greatly appreciated.  Is there a way I can combine/merge items from 2 multiselect list boxes to populate in a single drop-down so that the dorpdown shows all items selected from the 2 ...

substring(eval(eval((Users | AdditionalUsers)[. != ""], 'concat("; ", .)'), ".."), 2)

My latest thing is changing the colors on EVERYTHING so I can see what is taking up space. But you might want to use a single section and put in 11 expression boxes (calculated values) and show / hide the expression boxes instead of the section....

I have set all rows in all tables in all sections to auto for height. Still I have one px (or maybe 1pt) worth of space for each hidden section. I have a form with 10 major columns and a help button for each. There are eleven hidden sections between the heading row and the detail rows. So there are 11 pixels of space until you click a help button. ...

That works great thanks Jimmy, i'm 99% there, the only problem now is that if i have a blank repeating dropdown group it still puts in a ";" in the concat field, it isn't until you delete the repeating group that the preceeding ";" disappears. I think that is clear. Cheers, Rich

How about this: substring(eval(eval(Users | AdditionalUsers, 'concat("; ", .)'), ".."), 2)

Using 2010 I have a SQL view - SELECT c.ClientID, c.ClientName, p.ProjectID, v.VendorID, f.FeedID FROM  tbl_Clients c INNER JOIN       tbl_Projects p ON c.ClientID = p.ClientID INNER JOIN       tbl_Feeds f ON p.ProjectID = f.ProjectID INNER JOIN       tbl_Vendors v ON f.VendorID ...

 Wondering if you found the answer to this question?  I'm also a newbie and have the exact same question.