Code

Re: Position of current node

Agni Jonnalagadda — Wed, 09 Nov 2005 22:15:37 GMT

Hi Thierry,
Sorry for being late!
Here is one of the ways you can get position of current row,

//Get the list of nodes that are preceeding the present node
IXMLDOMNodeList preceedingNodesList = thisNode.selectNodes("preceding-sibling::RepeatingNode");
//Get the count of the preceeding nodes and add 1 to get the position of this node
int position= preceedingNodesList.length + 1;

Hope this helps!

Agni
InfoPath Dev India

Re: Position of current node

Coita Thierry — Wed, 09 Nov 2005 13:35:52 GMT

ok no problem thanks a lot!

I have found another way that work great now!

But if Agni can explain me his solution I will be very happy!

Agni if your hear me..

++

Thierry

Every moment hesitated is a moment gone for life!!! Think about it

Re: Position of current node

franck — Wed, 09 Nov 2005 06:22:52 GMT

Nope, sorry. Maybe Agni could jump back on this one...

Re: Position of current node

Coita Thierry — Tue, 08 Nov 2005 07:40:30 GMT

Hi Franck,

Merci pour la réponse!

I was mistaken (je me suis trompé) I can use e.source for select my correct node and make my replacechild with it!

But I don't know how to know my position? Is for another field that I need to find it!

with e.source that don't seems to work that send me always :"-1"

Any idea?

Thanks

Every moment hesitated is a moment gone for life!!! Think about it

Re: Position of current node

franck — Mon, 07 Nov 2005 17:59:05 GMT

Hi Thierry,

I am confused here. Isn't "getNode" a function somewhere that has code in it around: e.Source.select...?

Franck

Position of current node

Coita Thierry — Mon, 07 Nov 2005 15:31:33 GMT

Hi,

I use c# for coding!

I have a master/detail table and I need to know which row it is when I click on the button! the button is in detail table

How I can make this? Agni has give me some idea in a previous post he has write:

quote:

Hi,
If the button is in the row, "e.Source" will get you the selected row.

If the button is at the bottom you can use

//xPath should poin to the Repeating node
IXMLDOMNode oNodes = getNode("/RootNode/RepeatingNode");]

//"CTRL22":- you will get this when you see the view.xsl file for that particular repeating table
int iMemberId = Convert.ToInt32(thisXDocument.GetNamedNodeProperty(oNodes, "CTRL22", "-1"));

This above line will get you the selected the rowID. With that row id you can get the node.

Agni
InfoPathDev India

I don't think I can use e.source this time but for the other method that makes me an error on getNode that say :

getNodes doesn't exist in the class or in the namespace ...

Thanks for your help!

++

Thierry

Every moment hesitated is a moment gone for life!!! Think about it