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<?xml-stylesheet type="text/xsl" href="https://www.infopathdev.com:443/utility/FeedStylesheets/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/"><channel><title>General</title><link>https://www.infopathdev.com:443/forums/41.aspx</link><description>If you're not sure where to ask your question, ask it here. If necessary, our moderators will make sure it gets classified in the correct board.</description><dc:language>en</dc:language><generator>CommunityServer 2007 SP3 (Build: 31118.962)</generator><item><title>Link to a Page and Source back to an InfoPath edit form with the correct ID</title><link>https://www.infopathdev.com:443/forums/thread/95621.aspx</link><pubDate>Mon, 03 Feb 2014 15:59:49 GMT</pubDate><guid isPermaLink="false">033a2e2d-04e2-4a9d-be01-a4634161eefd:95621</guid><dc:creator>Michael71</dc:creator><slash:comments>0</slash:comments><comments>https://www.infopathdev.com:443/forums/thread/95621.aspx</comments><wfw:commentRss>https://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=41&amp;PostID=95621</wfw:commentRss><description>&lt;p&gt;Hello All,&lt;/p&gt;&lt;p&gt;This may be simple, but I&amp;#39;ve been having trouble doing this. I put a link on an Edit Form page and now I want&amp;nbsp;the Link to&amp;nbsp;go to an upload pag and Source back to an InfoPath edit form with the correct ID and data showing. Any help would be appreciated.&lt;/p&gt;&lt;p&gt;Michael&lt;/p&gt;</description></item></channel></rss>