https://www.infopathdev.com:443/forums/41.aspxIf you're not sure where to ask your question, ask it here. If necessary, our moderators will make sure it gets classified in the correct board.enCommunityServer 2007 SP3 (Build: 31118.962)https://www.infopathdev.com:443/forums/thread/88824.aspxWed, 10 Apr 2013 15:30:10 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:88824ebonymb0https://www.infopathdev.com:443/forums/thread/88824.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=41&PostID=88824<p>I knew it was something simple.&nbsp; Thanks much!</p>https://www.infopathdev.com:443/forums/thread/88820.aspxWed, 10 Apr 2013 15:20:15 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:88820ErnestoM0https://www.infopathdev.com:443/forums/thread/88820.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=41&PostID=88820<p>Have you tried this?</p><p>1000 + count(ID)</p>https://www.infopathdev.com:443/forums/thread/88797.aspxTue, 09 Apr 2013 17:25:16 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:88797ebonymb0https://www.infopathdev.com:443/forums/thread/88797.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=41&PostID=88797<p>I have a field that counts the number of existing items in a list.&nbsp; count(ID).&nbsp; I would like to add this count to 1000 to get a 4 digit incremental identifier.&nbsp; Any idea what formula I could use to get this result?</p>