General

Re: execute a resource file form code?

ek38 — Mon, 27 Feb 2012 14:57:17 GMT

Jimmy,

Anson provided me with an example of how to do it. The answer involved "Code". I do not know execute a resource file in code so I added a thread to the "code" forum seeking an example in JScript.

Can you elaborate on the commands in JScript to do this?

Re: execute a resource file form code?

Jimmy — Tue, 21 Feb 2012 16:40:13 GMT

Hi ek38,

It seems you already asked this in a separate thread. Any reason you started up a new one? It looks like your Process.Start() approach was probably the most appropriate way to go, but perhaps the process wasn't starting up in the right path. Have you tried explicitly specifying the full path?

execute a resource file form code?

ek38 — Tue, 21 Feb 2012 15:36:08 GMT

I want to call a ".bat" file or a ".cmd" file located on the local C drive from within an infopath form. It was suggested I add the file as a "resource" file, which I did. Now, how do I execute that resource file within code? JScript example would be very helpful.

Re: Unable to find batch file

ek38 — Mon, 20 Feb 2012 15:57:11 GMT

Anson,

No I have not. To be honest, I never have used that feature of Infopath. I will read-up and give it a try.

Thanks

Re: Unable to find batch file

Anson Hidajat — Wed, 15 Feb 2012 19:18:43 GMT

Have you tried including the file as a resource of the template instead and then referring that file in code? Go to Data tab -> Resource Files.

Unable to find batch file

ek38 — Tue, 14 Feb 2012 14:00:59 GMT

We have an infopath form with a button. When the user clicks the button, code is executed. It simply runs a file located on the "C" drive

objShell.ShellExecute("ListShipDocsToBeImported.cmd");

Often, the user will get a message "Windows cannot find ListShipDocsToBeImported.cmd. Make sure you typed the name correctly and try again."

The users work around is to reboot the computer and then it will work. The form is located in a directory called C:\aoe. The cmd file is also located in the same directory.