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Re: Combine eval functions?

shniggens — Thu, 06 Oct 2011 18:02:39 GMT

Perfect. Oh, man, thank you very much!!!!!

Re: Combine eval functions?

Alec Pojidaev — Thu, 06 Oct 2011 17:40:10 GMT

Just concat them together. If the field does not exist its value will be an empty string:

eval(eval((EmployeeNextels1[EmployeeRadio = "Yes"]|EmployeeNextels2[EmployeeRadio = "Yes"]), 'concat(my:EmployeeNextel,my:TotallyDifferentField, ", ")'), "..")

Re: Combine eval functions?

shniggens — Thu, 06 Oct 2011 17:28:51 GMT

What if they don't both contain the field "EmployeeNextel"? The second one has a field called "StaffNextel" instead.

Re: Combine eval functions?

Alec Pojidaev — Thu, 06 Oct 2011 17:24:30 GMT

Yes. Assuming both repeating tables have field EmployeeNextel:

eval(eval((EmployeeNextels1[EmployeeRadio = "Yes"]|EmployeeNextels2[EmployeeRadio = "Yes"]), 'concat(my:EmployeeNextel, ", ")'), "..")

Combine eval functions?

shniggens — Thu, 06 Oct 2011 17:01:52 GMT

I am using an eval function to populate a text field from repeating table rows -

eval(eval(EmployeeNextels[EmployeeRadio = "Yes"], 'concat(my:EmployeeNextel, ", ")'), "..")

This formula is the default value of the text box being populated.

Is it possible to combine eval functions so that it gets it's value from two seperate repeating tables?