https://www.infopathdev.com:443/forums/41.aspxIf you're not sure where to ask your question, ask it here. If necessary, our moderators will make sure it gets classified in the correct board.enCommunityServer 2007 SP3 (Build: 31118.962)https://www.infopathdev.com:443/forums/thread/6507.aspxTue, 15 Feb 2005 15:35:42 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:6507Greg Collins0https://www.infopathdev.com:443/forums/thread/6507.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=41&PostID=6507It is fairly easy to modify the view .xsl file to use the concat() function to show both fields in the drop-down list.<br /><br />i.e. concat(my:item, ": ", my:description)<br /><br />The concat is just be used for the display value. This would not affect the stored value at all.<br /><br />Greg Collins [InfoPath MVP]https://www.infopathdev.com:443/forums/thread/4553.aspxMon, 14 Feb 2005 20:47:07 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:4553rlindstrom0https://www.infopathdev.com:443/forums/thread/4553.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=41&PostID=4553We have a requirement where a drop-down list box would need 2 columns. (Item / Description) I would need to show both columns/fields because the description helps the user pick the correct item. Only the item would be stored in the field. I could use a secondary data source or store the list directly in the form - How can this be done and what is the best approach to accomplish this?<br /><br />Thanks