Re: XPath Example?

Jeff.Wang — Fri, 28 Sep 2007 02:28:16 GMT

It works if you use following codes:

my:People/my:Person/my:Email[../my:Name = ../../../my:QueryName]

You can simply do this using the "Filter Data..." option in the "Select a Field or Group" dialog.

jeff.

Re: XPath Example?

davidair — Thu, 27 Sep 2007 00:22:13 GMT

You probably want something along the lines of: /my:People/my:Person[my:Name = ../../my:QueryName]/my:Email

XPath Example?

bspolarich — Wed, 26 Sep 2007 23:19:23 GMT

I want to be able to query a repeating table for a particular row matching a simple dynamic condition. I'm new to XPath so I'm sure this is a dumb question.

Say I have a DataSource like this:

People

- Person

-- Name

-- Email

QueryName

QueryEmail

I want to be able to enter a name into QueryName and have it display the correct Email from the People collection based on Name matching QueryName.

If I'm stupid about it I do this: ../my:People/my:Person/my:Email

But that just always returns the Email value from the first element of the repeating section.

So I start playing with XPath expressions. For example: ../my:People/my:Person[last()]/my:Email returns the Email from the last group in the section.

But how do I do a @ statement? Nothing seems to work. If I try to insert fields in the XPath I get complaints about "node-test expected" unless I strip off the "../" portion, and then nothing happens when I try that.

I obviously have to cut my teeth on this XML stuff a bit more :-) but pointers would be appreciated.

General

Re: XPath Example?

Re: XPath Example?

XPath Example?