https://www.infopathdev.com:443/forums/39.aspxNew to InfoPath? Search to see if your question has already been answered. If it has not, then ask it here or the appropriate topic forum.enCommunityServer 2007 SP3 (Build: 31118.962)https://www.infopathdev.com:443/forums/thread/43057.aspxWed, 17 Jun 2009 03:38:52 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:43057Jimmy0https://www.infopathdev.com:443/forums/thread/43057.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=39&PostID=43057<p>&nbsp;Well to start you off,</p><p>1. (@Delivery_Quote - @Fully_Loaded / 60)</p><p>2. (@Actual_Zone_DT / TotalNumberOfLifts + 10)</p><p>3. I don&#39;t know what you mean by &quot;all of the above.&quot;&nbsp; How should we combine 1 and 2?&nbsp; Add? Multiply? It would be either:</p><p>((@Delivery_Quote - @Fully_Loaded / 60) + (@Actual_Zone_DT / TotalNumberOfLifts + 10)) / @Delivery_Quote</p><p>or</p><p>((@Delivery_Quote - @Fully_Loaded / 60) * (@Actual_Zone_DT / TotalNumberOfLifts + 10)) / @Delivery_Quote</p>https://www.infopathdev.com:443/forums/thread/43053.aspxWed, 17 Jun 2009 02:47:48 GMT033a2e2d-04e2-4a9d-be01-a4634161eefd:43053mbrady19730https://www.infopathdev.com:443/forums/thread/43053.aspxhttps://www.infopathdev.com:443/forums/commentrss.aspx?SectionID=39&PostID=43053<p>Hello,</p> <p>&nbsp;Could someone help me w/the following formula?</p> <p>&nbsp;(@Delivery_Quote - ((@Fully_Loaded / 60) * (@Actual_Zone_DT / TotalNumberOfLifts)) + 10) / ((@Delivery_Quote))</p> <p>&nbsp;It should happen in this order;</p> <ol> <li> <div>Delivery Quote - (Fully Loaded / 60)</div></li> <li> <div>(Actual Zone DT / TotalNumberOfLifts) + 10</div></li> <li> <div>All of the above divided by delivery quote</div></li></ol> <p>For some reason, I can&#39;t get the parentheses in the proper order.</p> <p>Thanks</p>