Get Attachment Filename in InfoPath 2010

Wan Abdul Malik — Sat, 07 Feb 2015 05:25:15 GMT

I want to insert the filename from the file (Attachment1) attached inside the form into the textbox (AttachmentComment).
Below shows the source code inside my InfoPath form.

I got an error related to DOM. Below shows the error:

Error 1 An object reference is required for the nonstatic field, method, or property 'Microsoft.Office.Interop.InfoPath.SemiTrust._XDocument2.DOM.get' C:\Users\spdev\Documents\InfoPath Projects\TQ_submission_form_v3_12\FormCode.cs 64 19 TQ_submission_form_v3_1

Error 2 The name 'thisXDocument' does not exist in the current context C:\Users\spdev\Documents\InfoPath Projects\TQ_submission_form_v3_12\FormCode.cs 94 17 TQ_submission_form_v3_1

________________________________________________________________________________________________

using Microsoft.Office.InfoPath;

using System;

using System.Xml;

using System.Xml.XPath;

using System.Xml.Linq;

using Microsoft.Office.Interop.InfoPath.SemiTrust;

================================================================================

[InfoPathEventHandler(MatchPath = "/my:myFields/my:Attachment/my:Attachment1",

EventType = InfoPathEventType.OnAfterChange)]

public void attachedDoc_OnAfterChange(DataDOMEvent e)

{

if (e.IsUndoRedo)

{

return;

}

RetrieveFilename();

}

public void RetrieveFilename()

{

try

{

IXMLDOMNode opnXN =

Microsoft.Office.Interop.InfoPath.SemiTrust.XDocument.DOM.

selectSingleNode("/my:myFields/my:Attachment/my:Attachment1");

byte[] attachmentNodeBytes =

Convert.FromBase64String(opnXN.nodeTypedValue

.ToString());

int fnLength = attachmentNodeBytes[20] * 2;

byte[] fnBytes = new byte[fnLength];

for (int i = 0; i < fnBytes.Length; i++)

{

fnBytes[i] = attachmentNodeBytes[24 + i];

}

char[] charFileName =

System.Text.UnicodeEncoding.Unicode.GetChars(fnBytes);

string fileName = new string(charFileName);

fileName = fileName.Substring(0, fileName.Length - 1);

thisXDocument.DOM.

selectSingleNode("/my:myFields/my:Attachment/my:AttachmentComment").text

= fileName;

}

catch (Exception e)// TODO: Write better error handler

{

System.Diagnostics.Debug.WriteLine(e.ToString());

}