InfoPath Dev

Which is the simplest way to insert an XML node in a different view?
ExcuteAction?AppendChild?

ExecuteAction only works on fields physically present in the current view.

AppendChild works directly on the XML and will work regardless of whether the fields are present in the current view.

Which is more simple? Depends on your comfort level with each...

Greg Collins [InfoPath MVP]
InfoPath Dev

Hi, I tried with AppendChild in this way:

dim objDoc
set objDoc = CreateObject("Msxml2.DOMDocument.5.0")
objDoc.setProperty "SelectionNamespaces", "xmlns:dfs=""http://schemas.microsoft.com/office/infopath/2003/dataFormSolution"" " & "xmlns:my=""http://schemas.microsoft.com/office/infopath/2003/myXSD/2005-06-29T14:42:29"" "

stringXML="<my:Plant> .... </my:Plant>"

objDoc.loadXML(stringXML)
objDoc.async = false

dim oParentNode
set oParentNode = XDocument.DOM.selectSingleNode("//my:Sezione1")

dim Node
set Node = objDoc.selectSingleNode("//my:Plant")
oParentNode.appendChild(Node)


but Infopath can't load stringXML becouse of "Reference to an undeclered namespace 'my'"; so I tried to change stringXML:

stringXML="<my:Plant xmlns:my=""http://schemas.microsoft.com/office/infopath/2003/myXSD/2005-06-29T14:42:29> .... </my:Plant>"

But this time there's another error:
"Element 'http://schemas.microsoft.com/office/infopath/2003/myXSD/2005-06-29T14:42:29}Plant' is unexpected according to content model of parent element 'http://schemas.microsoft.com/office/infopath/2003/myXSD/2005-06-29T14:42:29}Sezione1'."

How can I make this code work!? :)))
Thank you all!