InfoPath Dev

I am trying to change views twice. The first change view occurs at when the user clicks on a print button. The view switches to the particular print view and then through jscript(using.PrintOut()) the form prints. Then I try to change the view in the script using the .SwitchView("") and I get an error: InfoPath cannot execute any view-related object model calls. The view is not ready.

I imagine I have forgotten to add something but for the life of me...

Please provide insight to what I need to do to have the view return to the default once the form has printed?

"One Line at a Time" - anonymous codeaholic
Greg McAllister

I think what you are doing is
1. First switch to the print view as a rule on the button
2. Then in the onclick function PrintOut() happens
3. At the end of the onClick function you are doing a switch view back to the main view

This problems seems to be solved when when the first switchView() is also called in the code instead of calling it as a rule.

Do i have the issue correctly? or are you doing something different?

Shanthi
InfoPathDev India

You are correct but I have tried the combination you suggested and get the same error when it tries to switch back. Thanks fo trying - any other possibilities?

"One Line at a Time" - anonymous codeaholic
Greg McAllister

Did this problem get solved? If not, can you paste your code in here. This code is being run onClick of a button correct?

Shanthi
InfoPathDev India

InfoPath does not allow you to switch views, during a view switch. You may not think you are doing that, but you likely are (so far as InfoPath is concerned).

Greg Collins [InfoPath MVP]
InfoPathDev